(9y+7)=(2y+28)

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Solution for (9y+7)=(2y+28) equation: 



(9y+7)=(2y+28)

We move all terms to the left:

(9y+7)-((2y+28))=0

We get rid of parentheses

9y-((2y+28))+7=0



We calculate terms in parentheses: -((2y+28)), so:

(2y+28)

We get rid of parentheses

2y+28

Back to the equation:

-(2y+28)



We get rid of parentheses

9y-2y-28+7=0

We add all the numbers together, and all the variables

7y-21=0

We move all terms containing y to the left, all other terms to the right

7y=21

y=21/7

y=3

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