(9y+7)=(2y+28)

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Solution for (9y+7)=(2y+28) equation:



(9y+7)=(2y+28)
We move all terms to the left:
(9y+7)-((2y+28))=0
We get rid of parentheses
9y-((2y+28))+7=0
We calculate terms in parentheses: -((2y+28)), so:
(2y+28)
We get rid of parentheses
2y+28
Back to the equation:
-(2y+28)
We get rid of parentheses
9y-2y-28+7=0
We add all the numbers together, and all the variables
7y-21=0
We move all terms containing y to the left, all other terms to the right
7y=21
y=21/7
y=3

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