(9y-2)/2=(y-3)/3

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Solution for (9y-2)/2=(y-3)/3 equation: 



(9y-2)/2=(y-3)/3

We move all terms to the left:

(9y-2)/2-((y-3)/3)=0

We calculate fractions


9y/()+(-((y-3)*2)/()=0



We calculate terms in parentheses: +(-((y-3)*2)/(), so:

-((y-3)*2)/(

We multiply all the terms by the denominator


-((y-3)*2)



We calculate terms in parentheses: -((y-3)*2), so:

(y-3)*2

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)



We get rid of parentheses

-2y+6

Back to the equation:

+(-2y+6)



We get rid of parentheses

9y/()-2y+6=0

We multiply all the terms by the denominator


9y-2y*()+6*()=0

We add all the numbers together, and all the variables

9y-2y*()=0

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