(9y-3)=(4y+7)

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Solution for (9y-3)=(4y+7) equation: 



(9y-3)=(4y+7)

We move all terms to the left:

(9y-3)-((4y+7))=0

We get rid of parentheses

9y-((4y+7))-3=0



We calculate terms in parentheses: -((4y+7)), so:

(4y+7)

We get rid of parentheses

4y+7

Back to the equation:

-(4y+7)



We get rid of parentheses

9y-4y-7-3=0

We add all the numbers together, and all the variables

5y-10=0

We move all terms containing y to the left, all other terms to the right

5y=10

y=10/5

y=2

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