(9y-4)3=27y-12

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Solution for (9y-4)3=27y-12 equation: 



(9y-4)3=27y-12

We move all terms to the left:

(9y-4)3-(27y-12)=0

We multiply parentheses

27y-(27y-12)-12=0

We get rid of parentheses

27y-27y+12-12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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