(9z+3)+(3z-4)=

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Solution for (9z+3)+(3z-4)= equation:


Simplifying
(9z + 3) + (3z + -4) = 0

Reorder the terms:
(3 + 9z) + (3z + -4) = 0

Remove parenthesis around (3 + 9z)
3 + 9z + (3z + -4) = 0

Reorder the terms:
3 + 9z + (-4 + 3z) = 0

Remove parenthesis around (-4 + 3z)
3 + 9z + -4 + 3z = 0

Reorder the terms:
3 + -4 + 9z + 3z = 0

Combine like terms: 3 + -4 = -1
-1 + 9z + 3z = 0

Combine like terms: 9z + 3z = 12z
-1 + 12z = 0

Solving
-1 + 12z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 12z = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 12z = 0 + 1
12z = 0 + 1

Combine like terms: 0 + 1 = 1
12z = 1

Divide each side by '12'.
z = 0.08333333333

Simplifying
z = 0.08333333333

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