(9z+6)+(3z)=90

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Solution for (9z+6)+(3z)=90 equation: 



(9z+6)+(3z)=90

We move all terms to the left:

(9z+6)+(3z)-(90)=0

We add all the numbers together, and all the variables

3z+(9z+6)-90=0

We get rid of parentheses

3z+9z+6-90=0

We add all the numbers together, and all the variables

12z-84=0

We move all terms containing z to the left, all other terms to the right

12z=84

z=84/12

z=7

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