(9z-4)/5=(7z+2)/4

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Solution for (9z-4)/5=(7z+2)/4 equation: 



(9z-4)/5=(7z+2)/4

We move all terms to the left:

(9z-4)/5-((7z+2)/4)=0

We calculate fractions


9z/()+(-((7z+2)*5)/()=0



We calculate terms in parentheses: +(-((7z+2)*5)/(), so:

-((7z+2)*5)/(

We multiply all the terms by the denominator


-((7z+2)*5)



We calculate terms in parentheses: -((7z+2)*5), so:

(7z+2)*5

We multiply parentheses

35z+10

Back to the equation:

-(35z+10)



We get rid of parentheses

-35z-10

Back to the equation:

+(-35z-10)



We get rid of parentheses

9z/()-35z-10=0

We multiply all the terms by the denominator


9z-35z*()-10*()=0

We add all the numbers together, and all the variables

9z-35z*()=0

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