(A(A+4))=140

Solution for (A(A+4))=140 equation:

Simplifying
(A(A + 4)) = 140

Reorder the terms:
(A(4 + A)) = 140
((4 * A + A * A)) = 140
((4A + A2)) = 140
(4A + A2) = 140

Remove parenthesis around (4A + A2)
4A + A2 = 140

Solving
4A + A2 = 140

Solving for variable 'A'.

Reorder the terms:
-140 + 4A + A2 = 140 + -140

Combine like terms: 140 + -140 = 0
-140 + 4A + A2 = 0

Factor a trinomial.
(-14 + -1A)(10 + -1A) = 0

Subproblem 1
Set the factor '(-14 + -1A)' equal to zero and attempt to solve:

Simplifying
-14 + -1A = 0

Solving
-14 + -1A = 0

Move all terms containing A to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + -1A = 0 + 14

Combine like terms: -14 + 14 = 0
0 + -1A = 0 + 14
-1A = 0 + 14

Combine like terms: 0 + 14 = 14
-1A = 14

Divide each side by '-1'.
A = -14

Simplifying
A = -14
Subproblem 2
Set the factor '(10 + -1A)' equal to zero and attempt to solve:

Simplifying
10 + -1A = 0

Solving
10 + -1A = 0

Move all terms containing A to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1A = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1A = 0 + -10
-1A = 0 + -10

Combine like terms: 0 + -10 = -10
-1A = -10

Divide each side by '-1'.
A = 10

Simplifying
A = 10
Solution
A = {-14, 10}