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(/6)+(2A-3)/4=(7A/3)
We move all terms to the left:
(/6)+(2A-3)/4-((7A/3))=0
We add all the numbers together, and all the variables
(2A-3)/4-((+7A/3))+(+/6)=0
We get rid of parentheses
(2A-3)/4-((+7A/3))+/6=0
We calculate fractions
12A/()+(-((+7A*4*6)/()+()/()=0
We calculate terms in parentheses: +(-((+7A*4*6)/()+()/(), so:
-((+7A*4*6)/()+()/(
We can not solve this equation
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