(B(5x+1))/2=1779

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Solution for (B(5x+1))/2=1779 equation: 



((5B+1))/2=1779

We move all terms to the left:

((5B+1))/2-(1779)=0

We multiply all the terms by the denominator


((5B+1))-1779*2=0



We calculate terms in parentheses: +((5B+1)), so:

(5B+1)

We get rid of parentheses

5B+1

Back to the equation:

+(5B+1)



We add all the numbers together, and all the variables

(5B+1)-3558=0

We get rid of parentheses

5B+1-3558=0

We add all the numbers together, and all the variables

5B-3557=0

We move all terms containing B to the left, all other terms to the right

5B=3557

B=3557/5

B=711+2/5

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