(B+1)=(b+3)(b+2)

Solution for (B+1)=(b+3)(b+2) equation:

Simplifying
(B + 1) = (b + 3)(b + 2)

Reorder the terms:
(1 + B) = (b + 3)(b + 2)

Remove parenthesis around (1 + B)
1 + B = (b + 3)(b + 2)

Reorder the terms:
1 + B = (3 + b)(b + 2)

Reorder the terms:
1 + B = (3 + b)(2 + b)

Multiply (3 + b) * (2 + b)
1 + B = (3(2 + b) + b(2 + b))
1 + B = ((2 * 3 + b * 3) + b(2 + b))
1 + B = ((6 + 3b) + b(2 + b))
1 + B = (6 + 3b + (2 * b + b * b))
1 + B = (6 + 3b + (2b + b2))

Combine like terms: 3b + 2b = 5b
1 + B = (6 + 5b + b2)

Solving
1 + B = 6 + 5b + b2

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + B = 6 + 5b + -1 + b2

Combine like terms: 1 + -1 = 0
0 + B = 6 + 5b + -1 + b2
B = 6 + 5b + -1 + b2

Reorder the terms:
B = 6 + -1 + 5b + b2

Combine like terms: 6 + -1 = 5
B = 5 + 5b + b2

Simplifying
B = 5 + 5b + b2