(B+3)+(B)+(B-1)=26

Solution for (B+3)+(B)+(B-1)=26 equation:

Simplifying
(B + 3) + (B) + (B + -1) = 26

Reorder the terms:
(3 + B) + (B) + (B + -1) = 26

Remove parenthesis around (3 + B)
3 + B + (B) + (B + -1) = 26
3 + B + B + (B + -1) = 26

Reorder the terms:
3 + B + B + (-1 + B) = 26

Remove parenthesis around (-1 + B)
3 + B + B + -1 + B = 26

Reorder the terms:
3 + -1 + B + B + B = 26

Combine like terms: 3 + -1 = 2
2 + B + B + B = 26

Combine like terms: B + B = 2B
2 + 2B + B = 26

Combine like terms: 2B + B = 3B
2 + 3B = 26

Solving
2 + 3B = 26

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3B = 26 + -2

Combine like terms: 2 + -2 = 0
0 + 3B = 26 + -2
3B = 26 + -2

Combine like terms: 26 + -2 = 24
3B = 24

Divide each side by '3'.
B = 8

Simplifying
B = 8