(B-1)(B+5)=0

Solution for (B-1)(B+5)=0 equation:

Simplifying
(B + -1)(B + 5) = 0

Reorder the terms:
(-1 + B)(B + 5) = 0

Reorder the terms:
(-1 + B)(5 + B) = 0

Multiply (-1 + B) * (5 + B)
(-1(5 + B) + B(5 + B)) = 0
((5 * -1 + B * -1) + B(5 + B)) = 0
((-5 + -1B) + B(5 + B)) = 0
(-5 + -1B + (5 * B + B * B)) = 0
(-5 + -1B + (5B + B2)) = 0

Combine like terms: -1B + 5B = 4B
(-5 + 4B + B2) = 0

Solving
-5 + 4B + B2 = 0

Solving for variable 'B'.

Factor a trinomial.
(-5 + -1B)(1 + -1B) = 0

Subproblem 1
Set the factor '(-5 + -1B)' equal to zero and attempt to solve:

Simplifying
-5 + -1B = 0

Solving
-5 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1B = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1B = 0 + 5
-1B = 0 + 5

Combine like terms: 0 + 5 = 5
-1B = 5

Divide each side by '-1'.
B = -5

Simplifying
B = -5
Subproblem 2
Set the factor '(1 + -1B)' equal to zero and attempt to solve:

Simplifying
1 + -1B = 0

Solving
1 + -1B = 0

Move all terms containing B to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1B = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1B = 0 + -1
-1B = 0 + -1

Combine like terms: 0 + -1 = -1
-1B = -1

Divide each side by '-1'.
B = 1

Simplifying
B = 1
Solution
B = {-5, 1}