(B-4)/(6)=b/2

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Solution for (B-4)/(6)=b/2 equation: 


x in (-oo:+oo)

(B-4)/6 = b/2 // - b/2

(B-4)/6-(b/2) = 0

(B-4)/6-b/2 = 0

(2*(B-4))/(2*6)+(6*(-b))/(2*6) = 0

2*(B-4)+6*(-b) = 0

2*B-6*b-8 = 0

(2*B-6*b-8)/(2*6) = 0

(2*B-6*b-8)/(2*6) = 0 // * 2*6

2*B-6*b-8 = 0

x belongs to the empty set

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