(B-5)+(B)+2(B-5)=33

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Solution for (B-5)+(B)+2(B-5)=33 equation:


Simplifying
(B + -5) + (B) + 2(B + -5) = 33

Reorder the terms:
(-5 + B) + (B) + 2(B + -5) = 33

Remove parenthesis around (-5 + B)
-5 + B + (B) + 2(B + -5) = 33
-5 + B + B + 2(B + -5) = 33

Reorder the terms:
-5 + B + B + 2(-5 + B) = 33
-5 + B + B + (-5 * 2 + B * 2) = 33
-5 + B + B + (-10 + 2B) = 33

Reorder the terms:
-5 + -10 + B + B + 2B = 33

Combine like terms: -5 + -10 = -15
-15 + B + B + 2B = 33

Combine like terms: B + B = 2B
-15 + 2B + 2B = 33

Combine like terms: 2B + 2B = 4B
-15 + 4B = 33

Solving
-15 + 4B = 33

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 4B = 33 + 15

Combine like terms: -15 + 15 = 0
0 + 4B = 33 + 15
4B = 33 + 15

Combine like terms: 33 + 15 = 48
4B = 48

Divide each side by '4'.
B = 12

Simplifying
B = 12

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