(B/3)+7=2a-7a+2

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Solution for (B/3)+7=2a-7a+2 equation: 



(/3)+7=2B-7B+2

We move all terms to the left:

(/3)+7-(2B-7B+2)=0

We add all the numbers together, and all the variables

-(-5B+2)+7+(+/3)=0

We get rid of parentheses

5B-2+7+/3=0

We multiply all the terms by the denominator


5B*3-2*3+7*3+=0

We add all the numbers together, and all the variables

5B*3=0

Wy multiply elements

15B=0

B=0/15

B=0

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