(C+1)(2c+5)=0

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Solution for (C+1)(2c+5)=0 equation:


Simplifying
(C + 1)(2c + 5) = 0

Reorder the terms:
(1 + C)(2c + 5) = 0

Reorder the terms:
(1 + C)(5 + 2c) = 0

Multiply (1 + C) * (5 + 2c)
(1(5 + 2c) + C(5 + 2c)) = 0
((5 * 1 + 2c * 1) + C(5 + 2c)) = 0
((5 + 2c) + C(5 + 2c)) = 0
(5 + 2c + (5 * C + 2c * C)) = 0
(5 + 2c + (5C + 2cC)) = 0

Reorder the terms:
(5 + 5C + 2c + 2cC) = 0
(5 + 5C + 2c + 2cC) = 0

Solving
5 + 5C + 2c + 2cC = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + 5C + 2c + -5 + 2cC = 0 + -5

Reorder the terms:
5 + -5 + 5C + 2c + 2cC = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 5C + 2c + 2cC = 0 + -5
5C + 2c + 2cC = 0 + -5

Combine like terms: 0 + -5 = -5
5C + 2c + 2cC = -5

Add '-2c' to each side of the equation.
5C + 2c + -2c + 2cC = -5 + -2c

Combine like terms: 2c + -2c = 0
5C + 0 + 2cC = -5 + -2c
5C + 2cC = -5 + -2c

Reorder the terms:
5 + 5C + 2c + 2cC = -5 + -2c + 5 + 2c

Reorder the terms:
5 + 5C + 2c + 2cC = -5 + 5 + -2c + 2c

Combine like terms: -5 + 5 = 0
5 + 5C + 2c + 2cC = 0 + -2c + 2c
5 + 5C + 2c + 2cC = -2c + 2c

Combine like terms: -2c + 2c = 0
5 + 5C + 2c + 2cC = 0

The solution to this equation could not be determined.

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