(C+2)x(C-3)=14

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Solution for (C+2)x(C-3)=14 equation:



(+2)C(-3)=14
We move all terms to the left:
(+2)C(-3)-(14)=0
We add all the numbers together, and all the variables
2C(-3)-14=0
We multiply parentheses
-6C-14=0
We move all terms containing C to the left, all other terms to the right
-6C=14
C=14/-6
C=-2+1/3

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