(C+2)x(C-3)=14C=

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Solution for (C+2)x(C-3)=14C= equation: 



(+2)C(-3)=14=

We move all terms to the left:

(+2)C(-3)-(14)=0

We add all the numbers together, and all the variables

2C(-3)-14=0

We multiply parentheses

-6C-14=0

We move all terms containing C to the left, all other terms to the right

-6C=14

C=14/-6

C=-2+1/3

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