(C+3)-2c(-13c)=2

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Solution for (C+3)-2c(-13c)=2 equation: 



(+3)-2C(-13C)=2

We move all terms to the left:

(+3)-2C(-13C)-(2)=0

determiningTheFunctionDomain
-2C(-13C)-2+(+3)=0

We add all the numbers together, and all the variables

-2C(-13C)-2+3=0

We add all the numbers together, and all the variables

-2C(-13C)+1=0

We multiply parentheses

26C^2+1=0

a = 26; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·26·1
Δ = -104
Delta is less than zero, so there is no solution for the equation

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