(C+3)-2c+(-1)(1-3c)=2

Solution for (C+3)-2c+(-1)(1-3c)=2 equation:

Simplifying
(C + 3) + -2c + (-1)(1 + -3c) = 2

Reorder the terms:
(3 + C) + -2c + (-1)(1 + -3c) = 2

Remove parenthesis around (3 + C)
3 + C + -2c + (-1)(1 + -3c) = 2
3 + C + -2c + (1 * -1 + -3c * -1) = 2
3 + C + -2c + (-1 + 3c) = 2

Reorder the terms:
3 + -1 + C + -2c + 3c = 2

Combine like terms: 3 + -1 = 2
2 + C + -2c + 3c = 2

Combine like terms: -2c + 3c = 1c
2 + C + 1c = 2

Add '-2' to each side of the equation.
2 + C + -2 + 1c = 2 + -2

Reorder the terms:
2 + -2 + C + 1c = 2 + -2

Combine like terms: 2 + -2 = 0
0 + C + 1c = 2 + -2
C + 1c = 2 + -2

Combine like terms: 2 + -2 = 0
C + 1c = 0

Solving
C + 1c = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-1c' to each side of the equation.
C + 1c + -1c = 0 + -1c

Combine like terms: 1c + -1c = 0
C + 0 = 0 + -1c
C = 0 + -1c
Remove the zero:
C = -1c

Simplifying
C = -1c