(C+4)-4c-(1-2c)=3

Solution for (C+4)-4c-(1-2c)=3 equation:

Simplifying
(C + 4) + -4c + -1(1 + -2c) = 3

Reorder the terms:
(4 + C) + -4c + -1(1 + -2c) = 3

Remove parenthesis around (4 + C)
4 + C + -4c + -1(1 + -2c) = 3
4 + C + -4c + (1 * -1 + -2c * -1) = 3
4 + C + -4c + (-1 + 2c) = 3

Reorder the terms:
4 + -1 + C + -4c + 2c = 3

Combine like terms: 4 + -1 = 3
3 + C + -4c + 2c = 3

Combine like terms: -4c + 2c = -2c
3 + C + -2c = 3

Add '-3' to each side of the equation.
3 + C + -3 + -2c = 3 + -3

Reorder the terms:
3 + -3 + C + -2c = 3 + -3

Combine like terms: 3 + -3 = 0
0 + C + -2c = 3 + -3
C + -2c = 3 + -3

Combine like terms: 3 + -3 = 0
C + -2c = 0

Solving
C + -2c = 0

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '2c' to each side of the equation.
C + -2c + 2c = 0 + 2c

Combine like terms: -2c + 2c = 0
C + 0 = 0 + 2c
C = 0 + 2c
Remove the zero:
C = 2c

Simplifying
C = 2c