(C+43)+2c+(c+5)=180

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Solution for (C+43)+2c+(c+5)=180 equation: 



(+43)+2C+(C+5)=180

We move all terms to the left:

(+43)+2C+(C+5)-(180)=0

determiningTheFunctionDomain
2C+(C+5)-180+(+43)=0

We add all the numbers together, and all the variables

2C+(C+5)-180+43=0

We add all the numbers together, and all the variables

2C+(C+5)-137=0

We get rid of parentheses

2C+C+5-137=0

We add all the numbers together, and all the variables

3C-132=0

We move all terms containing C to the left, all other terms to the right

3C=132

C=132/3

C=44

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