(C-1)+2(3c+1)=(3c+1)

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Solution for (C-1)+2(3c+1)=(3c+1) equation: 



(-1)+2(3C+1)=(3C+1)

We move all terms to the left:

(-1)+2(3C+1)-((3C+1))=0

We add all the numbers together, and all the variables

2(3C+1)-((3C+1))-1=0

We multiply parentheses

6C-((3C+1))+2-1=0



We calculate terms in parentheses: -((3C+1)), so:

(3C+1)

We get rid of parentheses

3C+1

Back to the equation:

-(3C+1)



We add all the numbers together, and all the variables

6C-(3C+1)+1=0

We get rid of parentheses

6C-3C-1+1=0

We add all the numbers together, and all the variables

3C=0

C=0/3

C=0

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