(D/18)=(d+50)/20

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Solution for (D/18)=(d+50)/20 equation:



(/18)=(D+50)/20
We move all terms to the left:
(/18)-((D+50)/20)=0
We add all the numbers together, and all the variables
-((D+50)/20)+(+/18)=0
We get rid of parentheses
-((D+50)/20)+/18=0
We calculate fractions
(-((D+50)*18)/()+()/()=0
We calculate terms in parentheses: +(-((D+50)*18)/()+()/(), so:
-((D+50)*18)/()+()/(
We add all the numbers together, and all the variables
-((D+50)*18)/()+1
We multiply all the terms by the denominator
-((D+50)*18)+1*()
We calculate terms in parentheses: -((D+50)*18), so:
(D+50)*18
We multiply parentheses
18D+900
Back to the equation:
-(18D+900)
We add all the numbers together, and all the variables
-(18D+900)
We get rid of parentheses
-18D-900
Back to the equation:
+(-18D-900)
We get rid of parentheses
-18D-900=0
We move all terms containing D to the left, all other terms to the right
-18D=900
D=900/-18
D=-50

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