(E+3)x2=10

Solution for (E+3)x2=10 equation:

(+3)E2=10

We move all terms to the left:

(+3)E2-(10)=0

We add all the numbers together, and all the variables

3E2-10=0

We add all the numbers together, and all the variables

3E^2-10=0

a = 3; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·3·(-10)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$E_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*3}=\frac{0-2\sqrt{30}}{6}
=-\frac{2\sqrt{30}}{6}
=-\frac{\sqrt{30}}{3}
$
$E_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*3}=\frac{0+2\sqrt{30}}{6}
=\frac{2\sqrt{30}}{6}
=\frac{\sqrt{30}}{3}
$