(K+8)/k-(k-4)/k=3

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Solution for (K+8)/k-(k-4)/k=3 equation: 



(+8)/K-(K-4)/K=3

We move all terms to the left:

(+8)/K-(K-4)/K-(3)=0



Domain of the equation: K!=0

K∈R



We add all the numbers together, and all the variables

8/K-(K-4)/K-3=0

We multiply all the terms by the denominator


-(K-4)-3*K+8=0

We add all the numbers together, and all the variables

-3K-(K-4)+8=0

We get rid of parentheses

-3K-K+4+8=0

We add all the numbers together, and all the variables

-4K+12=0

We move all terms containing K to the left, all other terms to the right

-4K=-12

K=-12/-4

K=+3

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