(M-1)/5=(2m-3)/7-5

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Solution for (M-1)/5=(2m-3)/7-5 equation: 



(-1)/5=(2M-3)/7-5

We move all terms to the left:

(-1)/5-((2M-3)/7-5)=0

We calculate fractions


(-((2M-3)*5)/()+()/()=0



We calculate terms in parentheses: +(-((2M-3)*5)/()+()/(), so:

-((2M-3)*5)/()+()/(

We add all the numbers together, and all the variables

-((2M-3)*5)/()+1

We multiply all the terms by the denominator


-((2M-3)*5)+1*()



We calculate terms in parentheses: -((2M-3)*5), so:

(2M-3)*5

We multiply parentheses

10M-15

Back to the equation:

-(10M-15)



We add all the numbers together, and all the variables

-(10M-15)

We get rid of parentheses

-10M+15

Back to the equation:

+(-10M+15)



We get rid of parentheses

-10M+15=0

We move all terms containing M to the left, all other terms to the right

-10M=-15

M=-15/-10

M=1+1/2

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