(N)5(7f-3)=28(f-1)

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Solution for (N)5(7f-3)=28(f-1) equation:


Simplifying
(N) * 5(7f + -3) = 28(f + -1)

Reorder the terms:
N * 5(-3 + 7f) = 28(f + -1)

Reorder the terms for easier multiplication:
5N(-3 + 7f) = 28(f + -1)
(-3 * 5N + 7f * 5N) = 28(f + -1)
(-15N + 35fN) = 28(f + -1)

Reorder the terms:
-15N + 35fN = 28(-1 + f)
-15N + 35fN = (-1 * 28 + f * 28)
-15N + 35fN = (-28 + 28f)

Solving
-15N + 35fN = -28 + 28f

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Reorder the terms:
28 + -15N + -28f + 35fN = -28 + 28f + 28 + -28f

Reorder the terms:
28 + -15N + -28f + 35fN = -28 + 28 + 28f + -28f

Combine like terms: -28 + 28 = 0
28 + -15N + -28f + 35fN = 0 + 28f + -28f
28 + -15N + -28f + 35fN = 28f + -28f

Combine like terms: 28f + -28f = 0
28 + -15N + -28f + 35fN = 0

The solution to this equation could not be determined.

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