(N+9)-2=16x2

Solution for (N+9)-2=16x2 equation:

(+9)-2=16N^2

We move all terms to the left:

(+9)-2-(16N^2)=0

We add all the numbers together, and all the variables

-16N^2-2+9=0

We add all the numbers together, and all the variables

-16N^2+7=0

a = -16; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-16)·7
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$
$N_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{7}}{2*-16}=\frac{0-8\sqrt{7}}{-32}
=-\frac{8\sqrt{7}}{-32}
=-\frac{\sqrt{7}}{-4}
$
$N_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{7}}{2*-16}=\frac{0+8\sqrt{7}}{-32}
=\frac{8\sqrt{7}}{-32}
=\frac{\sqrt{7}}{-4}
$