(P+3)/7=(p-6)/3

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Solution for (P+3)/7=(p-6)/3 equation: 



(+3)/7=(P-6)/3

We move all terms to the left:

(+3)/7-((P-6)/3)=0

We add all the numbers together, and all the variables

-((P-6)/3)+3/7=0

We calculate fractions


(-((P-6)*7)/()+()/()=0



We calculate terms in parentheses: +(-((P-6)*7)/()+()/(), so:

-((P-6)*7)/()+()/(

We add all the numbers together, and all the variables

-((P-6)*7)/()+1

We multiply all the terms by the denominator


-((P-6)*7)+1*()



We calculate terms in parentheses: -((P-6)*7), so:

(P-6)*7

We multiply parentheses

7P-42

Back to the equation:

-(7P-42)



We add all the numbers together, and all the variables

-(7P-42)

We get rid of parentheses

-7P+42

Back to the equation:

+(-7P+42)



We get rid of parentheses

-7P+42=0

We move all terms containing P to the left, all other terms to the right

-7P=-42

P=-42/-7

P=+6

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