(Q-3)x2=14

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Solution for (Q-3)x2=14 equation: 



(-3)Q2=14

We move all terms to the left:

(-3)Q2-(14)=0

We multiply parentheses

-3Q^2-14=0

a = -3; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·(-3)·(-14)
Δ = -168
Delta is less than zero, so there is no solution for the equation

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