(Q-5)x2=12

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Solution for (Q-5)x2=12 equation: 



(-5)Q2=12

We move all terms to the left:

(-5)Q2-(12)=0

We multiply parentheses

-5Q^2-12=0

a = -5; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-5)·(-12)
Δ = -240
Delta is less than zero, so there is no solution for the equation

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