(R)+(r-8)+(2(r-8))=120

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Solution for (R)+(r-8)+(2(r-8))=120 equation:


Simplifying
(R) + (r + -8) + (2(r + -8)) = 120
R + (r + -8) + (2(r + -8)) = 120

Reorder the terms:
R + (-8 + r) + (2(r + -8)) = 120

Remove parenthesis around (-8 + r)
R + -8 + r + (2(r + -8)) = 120

Reorder the terms:
R + -8 + r + (2(-8 + r)) = 120
R + -8 + r + ((-8 * 2 + r * 2)) = 120
R + -8 + r + ((-16 + 2r)) = 120
R + -8 + r + (-16 + 2r) = 120

Remove parenthesis around (-16 + 2r)
R + -8 + r + -16 + 2r = 120

Reorder the terms:
-8 + -16 + R + r + 2r = 120

Combine like terms: -8 + -16 = -24
-24 + R + r + 2r = 120

Combine like terms: r + 2r = 3r
-24 + R + 3r = 120

Solving
-24 + R + 3r = 120

Solving for variable 'R'.

Move all terms containing R to the left, all other terms to the right.

Add '24' to each side of the equation.
-24 + R + 24 + 3r = 120 + 24

Reorder the terms:
-24 + 24 + R + 3r = 120 + 24

Combine like terms: -24 + 24 = 0
0 + R + 3r = 120 + 24
R + 3r = 120 + 24

Combine like terms: 120 + 24 = 144
R + 3r = 144

Add '-3r' to each side of the equation.
R + 3r + -3r = 144 + -3r

Combine like terms: 3r + -3r = 0
R + 0 = 144 + -3r
R = 144 + -3r

Simplifying
R = 144 + -3r

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