(R+5)/3=(4r-1)/2

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Solution for (R+5)/3=(4r-1)/2 equation: 



(+5)/3=(4R-1)/2

We move all terms to the left:

(+5)/3-((4R-1)/2)=0

We add all the numbers together, and all the variables

-((4R-1)/2)+5/3=0

We calculate fractions


(-((4R-1)*3)/()+()/()=0



We calculate terms in parentheses: +(-((4R-1)*3)/()+()/(), so:

-((4R-1)*3)/()+()/(

We add all the numbers together, and all the variables

-((4R-1)*3)/()+1

We multiply all the terms by the denominator


-((4R-1)*3)+1*()



We calculate terms in parentheses: -((4R-1)*3), so:

(4R-1)*3

We multiply parentheses

12R-3

Back to the equation:

-(12R-3)



We add all the numbers together, and all the variables

-(12R-3)

We get rid of parentheses

-12R+3

Back to the equation:

+(-12R+3)



We get rid of parentheses

-12R+3=0

We move all terms containing R to the left, all other terms to the right

-12R=-3

R=-3/-12

R=1/4

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