(R-6)/2=(r+4)/3

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Solution for (R-6)/2=(r+4)/3 equation: 



(-6)/2=(R+4)/3

We move all terms to the left:

(-6)/2-((R+4)/3)=0

We calculate fractions


(-((R+4)*2)/()+()/()=0



We calculate terms in parentheses: +(-((R+4)*2)/()+()/(), so:

-((R+4)*2)/()+()/(

We add all the numbers together, and all the variables

-((R+4)*2)/()+1

We multiply all the terms by the denominator


-((R+4)*2)+1*()



We calculate terms in parentheses: -((R+4)*2), so:

(R+4)*2

We multiply parentheses

2R+8

Back to the equation:

-(2R+8)



We add all the numbers together, and all the variables

-(2R+8)

We get rid of parentheses

-2R-8

Back to the equation:

+(-2R-8)



We get rid of parentheses

-2R-8=0

We move all terms containing R to the left, all other terms to the right

-2R=8

R=8/-2

R=-4

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