(W+3)2+4=(w-2)2+5w-2

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Solution for (W+3)2+4=(w-2)2+5w-2 equation: 



(+3)2+4=(W-2)2+5W-2

We move all terms to the left:

(+3)2+4-((W-2)2+5W-2)=0

We add all the numbers together, and all the variables

-((W-2)2+5W-2)+4+32=0

We add all the numbers together, and all the variables

-((W-2)2+5W-2)+36=0



We calculate terms in parentheses: -((W-2)2+5W-2), so:

(W-2)2+5W-2

We add all the numbers together, and all the variables

5W+(W-2)2-2

We multiply parentheses

5W+2W-4-2

We add all the numbers together, and all the variables

7W-6

Back to the equation:

-(7W-6)



We get rid of parentheses

-7W+6+36=0

We add all the numbers together, and all the variables

-7W+42=0

We move all terms containing W to the left, all other terms to the right

-7W=-42

W=-42/-7

W=+6

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