(X)(1+x)(2+x)=1320

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Solution for (X)(1+x)(2+x)=1320 equation: 



(X)(1+X)(2+X)=1320

We move all terms to the left:

(X)(1+X)(2+X)-(1320)=0

We add all the numbers together, and all the variables

X(X+1)(X+2)-1320=0

We multiply parentheses ..

X(+X^2+2X+X+2)-1320=0

We multiply parentheses

X^3+2X^2+X^2+2X-1320=0

We do not support eXpression: X^3

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