(X)+(x)+(2)+(x)+(4)+(x)+(6)=-28

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Solution for (X)+(x)+(2)+(x)+(4)+(x)+(6)=-28 equation:



(X)+(X)+(2)+(X)+(4)+(X)+(6)=-28
We move all terms to the left:
(X)+(X)+(2)+(X)+(4)+(X)+(6)-(-28)=0
We add all the numbers together, and all the variables
4X+40=0
We move all terms containing X to the left, all other terms to the right
4X=-40
X=-40/4
X=-10

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