(X)2+(x+12)=148

Solution for (X)2+(x+12)=148 equation:

(X)2+(X+12)=148

We move all terms to the left:

(X)2+(X+12)-(148)=0

We add all the numbers together, and all the variables

X^2+(X+12)-148=0

We get rid of parentheses

X^2+X+12-148=0

We add all the numbers together, and all the variables

X^2+X-136=0

a = 1; b = 1; c = -136;
Δ = b2-4ac
Δ = 12-4·1·(-136)
Δ = 545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{545}}{2*1}=\frac{-1-\sqrt{545}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{545}}{2*1}=\frac{-1+\sqrt{545}}{2}
$