(X+(2+5i))(X+(2-5i))=0

Simple and best practice solution for (X+(2+5i))(X+(2-5i))=0 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

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Solution for (X+(2+5i))(X+(2-5i))=0 equation: 



(X+(2+5X))(X+(2-5X))=0

We add all the numbers together, and all the variables

(X+(5X+2))(X+(-5X+2))=0



We calculate terms in parentheses: +(X+(5X+2))(X+(-5X+2)), so:

X+(5X+2))(X+(-5X+2)

We get rid of parentheses

X+(5X+2))(X-5X+2

We add all the numbers together, and all the variables

-4X+(5X+2))(X+2

Back to the equation:

+(-4X+(5X+2))(X+2)





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





We calculate terms in parentheses: +(-4X+(5X+2))(X+2), so:

-4X+(5X+2))(X+2





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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