(X+0.5)+(3x-2)=(3x+1.5)

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Solution for (X+0.5)+(3x-2)=(3x+1.5) equation:



(X+0.5)+(3X-2)=(3X+1.5)
We move all terms to the left:
(X+0.5)+(3X-2)-((3X+1.5))=0
We get rid of parentheses
X+3X-((3X+1.5))+0.5-2=0
We calculate terms in parentheses: -((3X+1.5)), so:
(3X+1.5)
We get rid of parentheses
3X+1.5
Back to the equation:
-(3X+1.5)
We add all the numbers together, and all the variables
4X-(3X+1.5)-1.5=0
We get rid of parentheses
4X-3X-1.5-1.5=0
We add all the numbers together, and all the variables
X-3=0
We move all terms containing X to the left, all other terms to the right
X=3

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