(X+1)(3x+10)=2x

Solution for (X+1)(3x+10)=2x equation:

(X+1)(3X+10)=2X

We move all terms to the left:

(X+1)(3X+10)-(2X)=0

We add all the numbers together, and all the variables

-2X+(X+1)(3X+10)=0

We multiply parentheses ..

(+3X^2+10X+3X+10)-2X=0

We get rid of parentheses

3X^2+10X+3X-2X+10=0

We add all the numbers together, and all the variables

3X^2+11X+10=0

a = 3; b = 11; c = +10;
Δ = b2-4ac
Δ = 112-4·3·10
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-1}{2*3}=\frac{-12}{6}
=-2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+1}{2*3}=\frac{-10}{6}
=-1+2/3
$