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(X+1)(7X+4)=0
We multiply parentheses ..
(+7X^2+4X+7X+4)=0
We get rid of parentheses
7X^2+4X+7X+4=0
We add all the numbers together, and all the variables
7X^2+11X+4=0
a = 7; b = 11; c = +4;
Δ = b2-4ac
Δ = 112-4·7·4
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-3}{2*7}=\frac{-14}{14} =-1 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+3}{2*7}=\frac{-8}{14} =-4/7 $
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