(X+1)(X+2)=(x-5)(x-6)

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Solution for (X+1)(X+2)=(x-5)(x-6) equation: 



(X+1)(X+2)=(X-5)(X-6)

We move all terms to the left:

(X+1)(X+2)-((X-5)(X-6))=0

We multiply parentheses ..

(+X^2+2X+X+2)-((X-5)(X-6))=0



We calculate terms in parentheses: -((X-5)(X-6)), so:

(X-5)(X-6)

We multiply parentheses ..

(+X^2-6X-5X+30)

We get rid of parentheses

X^2-6X-5X+30

We add all the numbers together, and all the variables

X^2-11X+30

Back to the equation:

-(X^2-11X+30)



We get rid of parentheses

X^2-X^2+2X+X+11X+2-30=0

We add all the numbers together, and all the variables

14X-28=0

We move all terms containing X to the left, all other terms to the right

14X=28

X=28/14

X=2

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