(X+1)(x+2)(x+3)=12

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Solution for (X+1)(x+2)(x+3)=12 equation: 



(X+1)(X+2)(X+3)=12

We move all terms to the left:

(X+1)(X+2)(X+3)-(12)=0

We multiply parentheses ..

(+X^2+2X+X+2)(X+3)-12=0

We move all terms containing X to the left, all other terms to the right

(+X^2+2X+X+2)(X+3)=12

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