(X+1)(x+2)=1320

Solution for (X+1)(x+2)=1320 equation:

(X+1)(X+2)=1320

We move all terms to the left:

(X+1)(X+2)-(1320)=0

We multiply parentheses ..

(+X^2+2X+X+2)-1320=0

We get rid of parentheses

X^2+2X+X+2-1320=0

We add all the numbers together, and all the variables

X^2+3X-1318=0

a = 1; b = 3; c = -1318;
Δ = b2-4ac
Δ = 32-4·1·(-1318)
Δ = 5281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{5281}}{2*1}=\frac{-3-\sqrt{5281}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{5281}}{2*1}=\frac{-3+\sqrt{5281}}{2}
$