(X+1)(x+7)=(x+1)(x+3)

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Solution for (X+1)(x+7)=(x+1)(x+3) equation: 



(X+1)(X+7)=(X+1)(X+3)

We move all terms to the left:

(X+1)(X+7)-((X+1)(X+3))=0

We multiply parentheses ..

(+X^2+7X+X+7)-((X+1)(X+3))=0



We calculate terms in parentheses: -((X+1)(X+3)), so:

(X+1)(X+3)

We multiply parentheses ..

(+X^2+3X+X+3)

We get rid of parentheses

X^2+3X+X+3

We add all the numbers together, and all the variables

X^2+4X+3

Back to the equation:

-(X^2+4X+3)



We get rid of parentheses

X^2-X^2+7X+X-4X+7-3=0

We add all the numbers together, and all the variables

4X+4=0

We move all terms containing X to the left, all other terms to the right

4X=-4

X=-4/4

X=-1

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