(X+1)*(3x+14)=0

Solution for (X+1)*(3x+14)=0 equation:

(X+1)(3X+14)=0

We multiply parentheses ..

(+3X^2+14X+3X+14)=0

We get rid of parentheses

3X^2+14X+3X+14=0

We add all the numbers together, and all the variables

3X^2+17X+14=0

a = 3; b = 17; c = +14;
Δ = b2-4ac
Δ = 172-4·3·14
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-11}{2*3}=\frac{-28}{6}
=-4+2/3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+11}{2*3}=\frac{-6}{6}
=-1
$