(X+1)+(3y+2)+(4y+2)=

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Solution for (X+1)+(3y+2)+(4y+2)= equation:


Simplifying
(X + 1) + (3y + 2) + (4y + 2) = 0

Reorder the terms:
(1 + X) + (3y + 2) + (4y + 2) = 0

Remove parenthesis around (1 + X)
1 + X + (3y + 2) + (4y + 2) = 0

Reorder the terms:
1 + X + (2 + 3y) + (4y + 2) = 0

Remove parenthesis around (2 + 3y)
1 + X + 2 + 3y + (4y + 2) = 0

Reorder the terms:
1 + X + 2 + 3y + (2 + 4y) = 0

Remove parenthesis around (2 + 4y)
1 + X + 2 + 3y + 2 + 4y = 0

Reorder the terms:
1 + 2 + 2 + X + 3y + 4y = 0

Combine like terms: 1 + 2 = 3
3 + 2 + X + 3y + 4y = 0

Combine like terms: 3 + 2 = 5
5 + X + 3y + 4y = 0

Combine like terms: 3y + 4y = 7y
5 + X + 7y = 0

Solving
5 + X + 7y = 0

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + X + -5 + 7y = 0 + -5

Reorder the terms:
5 + -5 + X + 7y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + X + 7y = 0 + -5
X + 7y = 0 + -5

Combine like terms: 0 + -5 = -5
X + 7y = -5

Add '-7y' to each side of the equation.
X + 7y + -7y = -5 + -7y

Combine like terms: 7y + -7y = 0
X + 0 = -5 + -7y
X = -5 + -7y

Simplifying
X = -5 + -7y

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